IGCSE Chemistry electrolysis: molten vs aqueous, and how to tell which product forms at the anode and cathode
Electrolysis is where students most often mix things up: when you get the metal, when H₂, when O₂ or the halogen. This guide boils it down to one set of rules that works for every question, lets you switch electrolytes in an animated cell and watch the ions move, and gives the half-equations and the words that lose marks.
The short answer
Remember 3 lines: PANIC (Positive is Anode, Negative Is Cathode) · positive ions go to the cathode, negative ions to the anode · OIL RIG (Oxidation Is Loss, Reduction Is Gain): the cathode gains electrons, so reduction; the anode loses them, so oxidation.
A molten compound always gives the metal at the cathode and the non-metal at the anode. An aqueous solution also has H⁺ and OH⁻ from water competing, so you need the selection rules in the next table.
In Edexcel 4CH1 this is points 1.55C–1.60C (C = Chemistry only, not in Double Award). The content matches 0620 almost exactly.
Molten vs aqueous: which ion is discharged
This table is every rule you need. Extended papers like to ask about a halide you have not met, such as concentrated KBr(aq), and the table answers it at once: K is more reactive than H, so H₂ at the cathode; Br⁻ is concentrated, so Br₂ at the anode.
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Ions in the cell
MoltenJust 2 kinds, from the compound, e.g. Pb²⁺ and Br⁻
Aqueous (in water)The compound's ions plus H⁺ and OH⁻ from water, competing to be discharged
Cathode (−) gives
MoltenAlways the metal
Aqueous (in water)The metal if it is less reactive than hydrogen (Cu, Ag); H₂ if it is more reactive (K, Na, Ca, Mg, Al, Zn, Fe)
Anode (+) gives
MoltenAlways the non-metal (a halogen, or O₂ from an oxide)
Aqueous (in water)The halogen from a concentrated halide; O₂ if it is dilute, or the anion is SO₄²⁻ / NO₃⁻ (never discharged)
Examples
MoltenPbBr₂ → Pb + Br₂ · Al₂O₃ (in cryolite) → Al + O₂
Aqueous (in water)Concentrated NaCl → H₂ + Cl₂ · CuSO₄ → Cu + O₂
Try it: switch the electrolyte and watch the ions
Close the switch and watch every positive ion drift to the cathode and every negative ion to the anode, while only one kind of ion is discharged at each electrode (thick outline); the rest bounce back as spectators. Compare concentrated with dilute NaCl, and CuSO₄ with graphite against copper electrodes.
- Cathode (−) · Product
- —
- Anode (+) · Product
- —
Rule: every + ion drifts to the cathode and every − ion to the anode, but only one ion is discharged at each electrode; the rest bounce back (spectators).
Products and half-equations for every cell that comes up
The 7 cells that come up most, with the products, ionic half-equations and observations in one place. In a half-equation the charges on both sides must match: electrons on the left at the cathode, on the right at the anode.
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Molten PbBr₂ (graphite) · Core
Cathode (−)Pb · Pb²⁺ + 2e⁻ → Pb
Anode (+)Br₂ · 2Br⁻ → Br₂ + 2e⁻
What you seeSilvery-grey lead below the cathode · red-brown vapour at the anode
Concentrated NaCl(aq) (graphite) · Core
Cathode (−)H₂ · 2H⁺ + 2e⁻ → H₂
Anode (+)Cl₂ · 2Cl⁻ → Cl₂ + 2e⁻
What you seeColourless bubbles at the cathode · pale green gas at the anode that bleaches damp litmus · NaOH left in solution
Dilute NaCl(aq) (graphite) · Extended
Cathode (−)H₂ · 2H⁺ + 2e⁻ → H₂
Anode (+)O₂ · 4OH⁻ → O₂ + 2H₂O + 4e⁻
What you seeColourless bubbles at both electrodes · the anode gas relights a glowing splint
Dilute H₂SO₄(aq) (graphite/Pt) · Core
Cathode (−)H₂ · 2H⁺ + 2e⁻ → H₂
Anode (+)O₂ · 4OH⁻ → O₂ + 2H₂O + 4e⁻
What you seeBubbles at both electrodes · twice the volume of H₂ as O₂
CuSO₄(aq) (graphite) · Extended
Cathode (−)Cu · Cu²⁺ + 2e⁻ → Cu
Anode (+)O₂ · 4OH⁻ → O₂ + 2H₂O + 4e⁻
What you seeRed-brown copper on the cathode · bubbles at the anode · the blue fades
CuSO₄(aq) (copper electrodes) · Extended
Cathode (−)Cu · Cu²⁺ + 2e⁻ → Cu
Anode (+)Cu²⁺ · Cu → Cu²⁺ + 2e⁻
What you seeCathode gains mass · anode loses mass, no bubbles · the blue stays the same
Al₂O₃ dissolved in molten cryolite (carbon) · Extended
Cathode (−)Al · Al³⁺ + 3e⁻ → Al
Anode (+)O₂ · 2O²⁻ → O₂ + 4e⁻
What you seeMolten aluminium collects at the bottom · O₂ burns the carbon anodes to CO₂, so they are replaced regularly
Electroplating, purifying copper and extracting aluminium
The real-world uses the exam asks about follow the same rules. What you must remember is which is the cathode, which is the anode, and what the electrolyte is.
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Electroplating
Cathode (−)The object to be plated
Anode (+)The plating metal, e.g. Ag, Ni, Cu
ElectrolyteA solution of a salt of the plating metal
What the question wantsDone to improve appearance and resistance to corrosion
Purifying copper
Cathode (−)Pure copper (gets thicker)
Anode (+)Impure copper (dissolves)
ElectrolyteCuSO₄(aq)
What the question wantsImpurities fall below the anode; the blue stays the same
Extracting aluminium
Cathode (−)Carbon lining, gives Al
Anode (+)Carbon, gives O₂
ElectrolyteAl₂O₃ dissolved in molten cryolite
What the question wantsCryolite lowers the melting point, saving energy · the anodes burn to CO₂ and are replaced
Brine (concentrated NaCl)
Cathode (−)Gives H₂
Anode (+)Gives Cl₂
ElectrolyteConcentrated NaCl(aq)
What the question wants3 products: H₂, Cl₂, and NaOH left in the solution
Words that lose marks
Most marks here go on wording, not knowledge. The most common slip is writing that electrons move through the electrolyte. Ions move in the electrolyte; electrons move in the wires (the external circuit).
For questions that start with Explain, see the phrases examiners want in Explain answers.
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How charge moves (Extended)
Loses the markelectrons move through the electrolyte
Scoresions move through the electrolyte; electrons move through the external circuit
What moves to the electrodes
Loses the markatoms / sodium moves to the cathode
Scorespositive ions (cations) move to the cathode; negative ions (anions) move to the anode
Why the ionic solid does not conduct
Loses the markthere are no free electrons
Scoresthe ions cannot move in the solid; they are free to move when molten or in solution
Cathode of NaCl(aq)
Loses the marksodium is formed
Scoreshydrogen is formed, because sodium is more reactive than hydrogen
Naming the anode gas
Loses the markCl (or 'chloride gas')
Scoreschlorine, Cl₂
The anode half-equation
Loses the mark2Cl⁻ + 2e⁻ → Cl₂
Scores2Cl⁻ → Cl₂ + 2e⁻ (electrons lost = oxidation)
A question asks what you see
Loses the markchlorine is produced
Scoresbubbles of pale green gas at the anode
Electroplating
Loses the markthe object is the anode
Scoresthe object is the cathode, the plating metal is the anode, and the electrolyte contains ions of the plating metal
Where Boom-Tutor helps
Topic 4 of the course (Electrochemistry) has 6 on-screen stations: cells and ions · products at the electrodes · electroplating · CuSO₄ with 2 kinds of electrode · halides and half-equations · fuel cells. The student builds the cell, sees the result, then answers exam-style questions straight away.
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